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Masteriza [31]
3 years ago
12

List the factors of 24 36 27 7

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0
The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. The factors of 36 are 1,2,3,4,6,9,12,18,36. The multiplication facts for 27 are 1 x 27, 27 x 1, 3 x 9 and 9 x 3. The factors of 7 are 1 and 7.
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Dawn simplified a power correctly and came up with a value of 64.
abruzzese [7]

Answer:

Hello fellow brainlian, I am pretty sure the answer is A)

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
PERSONAL EXEMPTIONS
WINSTONCH [101]
5151.56 - 3000 = 2151.56
5 0
3 years ago
Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
tester [92]

Given:

Polynomial is 3x^2+15x-56.

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

3x^2+15x-56+(x-8)^2

=3x^2+15x-56+x^2-2(x)(8)+8^2    [\because (a-b)^2=a^2-2ab+b^2]

=3x^2+15x-56+x^2-16x+64

On combining like terms, we get

=(3x^2+x^2)+(15x-16x)+(-56+64)

=4x^2-x+8

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 4x^2-x+8.

7 0
3 years ago
4log x-1/2log y+3log z
babymother [125]
Following rules of logs, we can do the following:

log x^4 - log y^(1/2) + log z^3

Combine the first and 3rd factors to get    log [x^4*z^3]

Seeing that the neg. sign signifies division, write this new term - log y^(1/2) as a quotient:

        [x^4*z^3]
log ----------------
           y^(1/2)

Next time, please include the instructions when you present your problem.
Thx.

7 0
3 years ago
Two teachers purchase supplies for their classrooms.
inna [77]

Answer:

Cost of One Journal =  $3.99

Cost of One pen =  $0.59

Step-by-step explanation:

Let

Cost of One Journal = x

Cost of One pen = y

We can make equation from given statements.

Mr. Bowden purchases 18 journals and 40 pencils for $95.42.

18x+40y=95.42

Ms. Jacinto purchases 11 journals and 16 pencils for $53.33.

11x+16y=53.33

Now solving these equations to find the value of x

18x+40y=95.42--eq(1)\\11x+16y=53.33--eq(2)

Multiply eq(1) with 2 and eq(2) with 5

36x+80y=190.84\\55x+80y=266.65\\-\:\:\:\:-\:\:\:\;\:\:\:\:\:\:\:-\\---------\\-19x=-75.81\\x=\frac{-75.81}{-19}\\x=3.99\\

We get the value of x is: x=3.99

Now, putting value of x in equation 1 to find value of y.

18x+40y=95.42\\18(3.99)+40y=95.42\\71.82+40y=95.42\\40y=95.42-71.82\\40y=23.6\\y=\frac{23.6}{40}\\y= 0.59

So, we get the value of y: y = 0.59

Now, finding the costs:

Cost of One Journal = x = $3.99

Cost of One pen = y = $0.59

7 0
3 years ago
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