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jeka57 [31]
3 years ago
12

Complete the flow map using the words product

Mathematics
1 answer:
amm18123 years ago
4 0
What Flow map??????? I need the flow map
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A house and a lot are appraised at $420000. If the value of the lot 3/4 of the value of the house, how much is the lot alone wor
34kurt

Hello from MrBillDoesMath!

Answer:

180000

Discussion:

Let H = house and L = lot. The Question tells us that H + L = 420000 and L = 3/4H. We are asked to solve for L

H        + L = 420000                => L = 3/4H implies that H =4/3L

(4/3)L + L = 420000               => (4/3) + 1 = 7/3

(7/3)L       = 420000               => multiply both sides by 3/7

(3/7)(7/3)L = (3/7)420000       => as (3/7)(7/3) = 1

L =  180000

Check:  

H + L                = 420000

H + 180000    = 420000

H                      = 420000 - 180000

H =                   =240000

Is L = 3/4H ?

Does     180000 = 3/4 ( 240000)   ?

Does     180000 = (3* 240000)/4 = 720000/4 = 180000  Yes! so the answers check!

Thank you,

MrB

3 0
4 years ago
You earn $35 for washing 7 cars. How much do you earn for washing 4 cars?
alexandr1967 [171]
43.75 , first divide 35 and 7 witch will give you 8.74 then multiply 8.75 by 4  
4 0
4 years ago
Read 2 more answers
Please help me find the slope between the two points m=​
abruzzese [7]
Answer: m= 5/2

explanation:
5- - 5 = 10
-4 - - 8 = 4
10/4= 5/2
8 0
3 years ago
It is 3 miles around Westwood Park exercise trail. After skating around the trail 5½ times, Mr. Zorn lost a wheel. How many mile
mart [117]
I hope this helps you




5 1/2=5.2+1/2=11/2



3.11/2


33/2


15 3/2


16,5
4 0
3 years ago
the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
Naily [24]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
5 0
4 years ago
Read 2 more answers
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