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3 years ago

Heres yo go mattty lolololololol

Mathematics

1 answer:

gladu [14]3 years ago

7 0

Answer:

x = 16

Step-by-step explanation:

71 - 15 = 56

56 ÷ 14 = 4

$\sqrt{16}$ = 4

Check work:

$\sqrt{16}$ = 4

14 x 4 = 56

56 + 15 = 71

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27x+3=6 what does x equal

Digiron [165]

Answer:

1/9

Step-by-step explanation:

27x+3 = 6

-3 -3

27x = 3

/27 /27

× = 3/27 = 1/9

8 0

3 years ago

Read 2 more answers

What is the domain of the function y=sqrt x?

vova2212 [387]

Square root is not defined to for negative values. For negative values, the answer of square root is a complex number which is not in Real Domain.

So any such values, for which the expression is not defined are not in the Domian. So the domian of square root of x will be All real numbers greater than or equal to 0.

This can be expressed as:

[0 , ∞)
or
x ≥ 0

8 0

2 years ago

Read 2 more answers

Help differentiate this

Arte-miy333 [17]

Answer:

$\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Terms/Coefficients
Expand by FOIL
Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = (x^3 + 7x - 1)(5x + 2)$

Step 2: Differentiate

Product Rule: $\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)]$
Basic Power Rule [Derivative Property - Addition/Subtraction]: $\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)$
Simplify: $\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)$
Expand: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)$
[Distributive Property] Distribute 5: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5$
Combine like terms: $\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$