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2 years ago

I have to factor 14 and 22 to find the greatest common factor

Mathematics

2 answers:

Monica [59]2 years ago

8 0

Answer: The GCF is 2

Bond [772]2 years ago

5 0

Answer:

Step-by-step explanation:

Solution by Factorization:

Hope this helps u :D

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Imagine two lines intersect. How can the properties of linear pairs and vertical angles help to determine the angle measures cre

Blizzard [7]

Answer:

A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees. Vertical angles are two angles opposite from each other and those two angles are then equal.

Step-by-step explanation:

For example, if you took your typical graph with four quadrants your lines would intersect. The linear pairs are equal to 180 and the vertical angles are equal.

8 0

2 years ago

A blueberry pie is shot out of a pie cannon from a height of 6m and with a velocity of 60 m/s. How many seconds will pass before

sveta [45]

Answer: 1.106 s

Step-by-step explanation:

This situation is related to projectile motion and one the equation that models the height of the blueberry pie in time is:

$y=y_{o}+V_{o}sin(\theta) t-\frac{1}{2}gt^{2}$

Where:

$y=0 m$ is the blueberry pie final height (when it hits the ground)

$y_{o}=6 m$ is the blueberry pie initial height

$V_{o}=60 m/s$ is the blueberry pie initial velocity

$\theta=0 \°$ is the angle, assuming the pie was shot horizontally

$t$ is the time

$g=9.8 m/s^{2}$ is the acceleration due gravity

Rewriting the equation:

$0=y_{o}-\frac{1}{2}gt^{2}$

Isolating $t$ :

$t=\sqrt{\frac{2y_{o}}{g}}$

$t=\sqrt{\frac{2(6 m)}{9.8 m/s^{2}}}$

Finally:

$t=1.106 s$

5 0

2 years ago

katherine bought cosmetic items which cost $78.12 in total she gave $100 to the shop keeper how much does she receive as change?

Leviafan [203]

Answer: $21.88 here is your answer.

7 0

2 years ago

Read 2 more answers

What are the domain and range of f(x) = 2(3^x)?

solong [7]

Answer:

Step-by-step explanation:

no x-intercept/zero

4 0

2 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

I have to factor 14 and 22 to find the greatest common factor​

I have to factor 14 and 22 to find the greatest common factor