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mezya [45]
3 years ago
9

Find the intercept form of y=2(x-1)(x+5)

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0
I think y=2x^2+8x-10
In case u don't know ^2 means square so don't put ^2 put the 2 next to the x on top cuz some ppl get confused
hoped I helped!:)
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How much Work is used when 25N of force is done over 100m?​
murzikaleks [220]

Step-by-step explanation:

we know that

Work =f*d

=25*100

=2500Joule

therefore work done is 2500Joule

4 0
2 years ago
Find the lateral area of the prism.<br> 4cm<br> 3cm <br> 6cm<br> 5cm<br> Lateral Area = [?]cm2
kolbaska11 [484]

Answer:

The lateral surface area of a prism is the sum of the surface areas of the sides of the prism.

Since the bases of the prism are triangles, there are three sides. The area of each lateral is the product of a side of the triangle times the height of the prism.

We can express this as Lateral Surface Area LSA = (s1xh) + (s2xh) + (s3+h), where "s1, s2, s3" are the lengths of the sides of the triangle and "h" is the height of the prism.

We can factor out "h" to get LSA = hx(s1+s2+s3) where the factor "s1+s2+s3" is the perimeter of the triangle.

Solving for "h", we get h = LSA / (s1+s2+s3)

For your specific problem, h = 300 / (4 + 5 + 6) = 300 / 15 = 20

4 0
2 years ago
What decimal is equivalent to 13/10
LUCKY_DIMON [66]

Answer:

1.30

Step-by-step explanation:

because it's 13 / 10 it means that there is a whole number , 13 - 10 equals 3 oh, so you divide 3 from 100

4 0
3 years ago
Please help.. I got stuck on this question please help and explain
Inessa [10]
Jay is wrong about his claim
8 0
3 years ago
Read 2 more answers
I'll mark brainliest just tell me how to.
IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

3 0
3 years ago
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