Answer:
3600
Step-by-step explanation:
Answer:
True!
Step-by-step explanation:
Distributive property
Answer:
The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Step-by-step explanation:
The three different assembly lines are: A₁, A₂ and A₃.
Denote <em>R</em> as the event that a component needs rework.
It is given that:

Compute the probability that a randomly selected component needs rework as follows:

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Answer:
0.1587
Step-by-step explanation:
Given the following :
Mean (m) of distribution = 64 inches
Standard deviation (sd) of distribution = 2 inches
Probability that a randomly selected woman is taller than 66 inches
For a normal distribution :
Z - score = (x - mean) / standard deviation
Where x = 66
P(X > 66) = P( Z > (66 - 64) / 2)
P(X > 66) = P(Z > (2 /2)
P(X > 66) = P(Z > 1)
P(Z > 1) = 1 - P(Z ≤ 1)
P(Z ≤ 1) = 0.8413 ( from z distribution table)
1 - P(Z ≤ 1) = 1 - 0.8413
= 0.1587