Describe the nature of the roots for this equation. 3x^2+x-5= 0

Mathematics

2 answers:

Colt1911 [192]3 years ago

7 0

Answer:

two real,irrational roots.

GOOD LUCK!

Step-by-step explanation:

m_a_m_a [10]3 years ago

4 0

Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

$3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}$

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laila [671]

You can write the amount that they spent individually in a ratio where:

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To find the scale factor multiplier for the base ratio of 2:5:

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5 0

2 years ago

Read 2 more answers

Solve for j : j/-2+7=-12 j=?

schepotkina [342]

Answer:

$\huge\boxed{j=38}$

Step-by-step explanation:

$\dfrac{j}{-2}+7=-12\qquad\text{subtract 7 from both sides}\\\\\dfrac{j}{-2}+7-7=-12-7\\\\\dfrac{j}{-2}=-19\qquad\text{multiply both sides by (-2)}\\\\(-2)\!\!\!\!\!\!\!\diagup\cdot\dfrac{j}{-2\!\!\!\!\!\diagup}=(-2)(-19)\\\\j=38$