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11111nata11111 [884]
3 years ago
13

Describe the nature of the roots for this equation. 3x^2+x-5= 0

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

Answer:

two real,irrational roots.

GOOD LUCK!

Step-by-step explanation:

m_a_m_a [10]3 years ago
4 0

Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}

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