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nordsb [41]
3 years ago
11

What is the volume of soup that will fit in a cylindrical-shaped can with a height that is 2 inches longer than the radius?

Mathematics
2 answers:
Drupady [299]3 years ago
6 0

Answer: V=\pi r^3+2\pi r^2

Step-by-step explanation:

Let r be the height of the cylinder then , the height of the cylinder will be (r+2).

The formula to find the volume of cylinder is given by :-

V=\pi r^2h

Then, the volume of the cylinder will be :-

V=\pi r^2((r+2))\\\\\Rightarrow\ V=\pi r^2(r)+\pi r^2(2)\\\\\Rightarrow\ V=\pi r^3+2\pi r^2

Hence, the volume of soup that will fit in a cylindrical-shaped can with a height that is 2 inches longer than the radius = V=\pi r^3+2\pi r^2

trasher [3.6K]3 years ago
4 0

Answer:

V = πr³ + 2πr²

Step-by-step explanation:

Volume of a cylinder:

V = πr²h

with radius r and height h = 2 + r:

V = πr²(2 + r) = πr³ + 2πr²

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As given by the question

There are given that the point of two-line

\begin{gathered} (1,\text{ 7) and (5, 5)} \\ (-1,\text{ -3) and (1, 1)} \end{gathered}

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For first-line, from the formula of slope

\begin{gathered} m_1=\frac{y_2-y_1}{x_2-x_1} \\ m_1=\frac{5_{}-7_{}}{5_{}-1_{}} \\ m_1=-\frac{2}{4} \\ m_1=-\frac{1}{2} \end{gathered}

Now,

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The given result of the slope is negative reciprocal because

\begin{gathered} -\frac{1}{2}=-(-\frac{2}{1}) \\ -\frac{1}{2}=2 \end{gathered}

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