Question

Rewrite the equation by completing the square. 4x^2 + 28x + 49=0

Answer 1

Answer:

$4(x+3.5)^{2}=0$

Step-by-step explanation:

we have

$4x^{2}+28x+49=0$

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(4x^{2}+28x)=-49$

step 2

Factor the leading coefficient

$4(x^{2}+7x)=-49$

step 3

Complete the square. Remember to balance the equation by adding the same constants to each side

$4(x^{2}+7x+3.5^2)=-49+(3.5^2)(4)$

$4(x^{2}+7x+12.25)=0$

step 4

Rewrite as perfect squares

$4(x+3.5)^{2}=0$