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3 years ago

How do I round 3.8129 to 3 decimal places?Please help!!!

2 answers:

6 0

$3.8129\\\\Since\ the\ fourth\ place\ is\ 5\ or\ more\ (here\ it's\ 9),\\the\ third\ place\ is\ increased\ by\ 1.\\\\Answer:3.8129\approx3.813$

Marianna [84]3 years ago

5 0

3.8129
rounded to 3 decimal places =3.813

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Answer:

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2 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

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Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

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For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

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For $r=0.88\ m$

assume

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$SA=4(3.14)(0.88)^{2}$

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Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

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substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

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we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

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The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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3 years ago

What is the area of the trapezoid?

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Answer:

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