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Xelga [282]
3 years ago
8

The perimeter of this rectangle is 156 cm.

Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

x = 15

Therefore, the length and width are 31 and 47.

Step-by-step explanation:

Perimeter = (2x + 1) + (2x + 1) + (3x + 2) + (3x + 2) = 156

Simplified,

10x + 6 = 156

Subtract 6 from both sides, then divide by 10.

10x = 150

x = 15

To find the length and width, substitute 15 (the value of x) into the individual equations.

2(15) + 1 = 31

3(15) + 2 = 47

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How do you do number 1?<br>Whenever I tried to answer it, I always get fraction. help me.​
Flura [38]

Answer:

The pairs are (13,15) and (-15,-13).

Step-by-step explanation:

If n is an odd integer, the very next odd integer will be n+2.

n+1 is even (so we aren't using this number)

The sum of the squares of (n) and (n+2) is 394.

This means

(n)^2+(n+2)^2=394

n^2+(n+2)(n+2)=394

n^2+n^2+4n+4=394               since (a+b)(a+b)=a^2+2ab+b^2

Combine like terms:

2n^2+4n+4=394

Subtract 394 on both sides:

2n^2+4n-390=0

Divide both sides by 2:

n^2+2n-195=0

Now we need to find two numbers that multiply to be -195 and add up to be 2.

15 and -13 since 15(-13)=-195 and 15+(-13)=2

So the factored form is

(n+15)(n-13)=0

This means we have n+15=0 and n-13=0 to solve.

n+15=0

Subtract 15 on both sides:

n=-15

n-13=0

Add 13 on both sides:

n=13

So if n=13 , then n+2=15.

If n=-15, then n+2=-13.

Let's check both results

(n,n+2)=(13,15)

13^2+15^2=169+225=394.  So (13,15) looks good!

(n,n+2)=(-15,-13)

(-15)^2+(-13)^2=225+169=394.  So (-15,-13) looks good!

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3 years ago
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Step-by-step explanation:

1.) First, you need to take the whole numbers (9 and 1) and set them aside.

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3.) Multiply the denominators by each other as well. The denominators are the numbers on the bottom. This will be the denominator of your answer.

4.) Now, you need to multiply your whole numbers (9 and 1) together.

5.) Then, simplify or reduce your answer. (this can't be simplified, as it is already in its simplest form)

Your answer will be 9 1/66.

Your work should look like this in the end:

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