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2 years ago

8

Wssp here are some pointss

1 answer:

Harlamova29_29 [7]2 years ago

6 0

So kind man so kinda dude

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Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationali

Otrada [13]

Answer:

the answer is 7

Step-by-step explanation:

angle 30°

x=14/2

x=7

8 0

3 years ago

Find the domain of (f/g)(x) when f(x)=1/x and g(x)=square root x+8

Alex_Xolod [135]

Step-by-step explanation:

all work is pictured/shown

6 0

2 years ago

Read 2 more answers

A tree casts a shadow 24 feet long. a 5 foot person casts a 8 foot shadow.How tall is the tree?

ra1l [238]

(length of tree's shadow)/(height of tree) = (length of person's shadow)/(person's height)

24/x = 8/5

24*5 = x*8

120 = 8x

8x = 120

8x/8 = 120/8

x = 15

The tree is 15 feet tall

8 0

3 years ago

Pls help with all the answers m

stiks02 [169]

Answer:

every answer except -40 and -20

answer:-77,-100,-45

8 0

3 years ago

Whats the roots of the following three problems:

klemol [59]

QUESTION 1

The given function is

$f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}$

We simplify to get;

$f(x)=\frac{x-3}{x+2}$

This function is equal to zero when $x-3=0$

$\Rightarrow x=3$

QUESTION 2

The given function is

$f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}$

$f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}$

We factor to get;

$f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}$

$f(x)=\frac{5(x-1)}{(2x-3)}$

This function equals zero when

$5(x-1)=0$

$x=1$

QUESTION 3

The given function is

$f(x)=\frac{x^3-8}{x^2-6x+8}$

We factor to get,

$f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}$

$f(x)=\frac{x^2+2x+4}{x+4}$

The function equals zero when $x^2+2x+4=0$

$D=b^2-4ac$

$D=2^2-4(1)(4)$

$D=-12$

Hence the equation has no real roots.

The complex roots are

$x=-\sqrt{3}i-1$ or $x=-1+\sqrt{3}i$

4 0

3 years ago