you times the 1/6 by 2 to get 2/12 then 3/4 by 3 to get 9/12 so all your fractions have the same denominator and the do the rest of the math with the new fractions and the same whole numbers that went with them. hope this helps

7 0

2 years ago

Read 2 more answers

Which graph best represents y= -x 2 + 2

nydimaria [60]

Answer:

Step-by-step explanation:

Is this y=-x^2 +2?

Here is the graph, in the photo.

Hope you understand

6 0

2 years ago

a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar

Margarita [4]

A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem:

$h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x$

thus,

$Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2$

thus:

$x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\ \sqrt{3} }{3}=24 \sqrt{3}$ (cm^2)

but $x^{2}$ is exactly the base area, since the base is a square of sidelength = x cm.

So, the total surface area = base area + lateral area = $24 \sqrt{3}+72$ cm^2

Answer: $24 \sqrt{3}+72$ cm^2

4 0

2 years ago

2(x-1)-y=-8 <br> y=2x+8 <br> substitution method

BartSMP [9]

Answer:

No Solution.

Step-by-step explanation:

2(x-1)-y=-8

y=2x+8

----------------

2x-2-(2x+8)=-8

2x-2-2x-8=-8

2x-2x-2-8=-8

0-2-8=-8

-2-8=-8

-10=-8

no solution

3 0

2 years ago