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sertanlavr [38]
3 years ago
13

A running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and

right edges of the track are identical curves. The top and bottom edges of the track are straight lines. The track has width 68 m and length of one straight edge 140 m. What is the perimeter of the inside of the track?
Mathematics
2 answers:
Minchanka [31]3 years ago
5 0
Two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.

Length = 140 m ; Width = 68 m

Circumference of a circle = 2 π r
circumference of a cirlce =  2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52

length = 2 * 140 m = 280 m

perimeter of the oval = 213.52 m + 280 m = 493.52 m
ad-work [718]3 years ago
3 0

Answer:

493.52

Step-by-step explanation:

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7 0
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Find all solutions ​
Anton [14]

Answer:

The solutions of the equation are 0 , π

Step-by-step explanation:

* Lets revise some trigonometric identities

- sin² Ф + cos² Ф = 1

- tan² Ф + 1 = sec² Ф

* Lets solve the equation

∵ tan² x sec² x + 2 sec² x - tan² x = 2

- Replace sec² x by tan² x + 1 in the equation

∴ tan² x (tan² x + 1) + 2(tan² x + 1) - tan² x = 2

∴ tan^4 x + tan² x + 2 tan² x + 2 - tan² x = 2 ⇒ add the like terms

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∴ tan^4 x + 2 tan² x = 0

- Factorize the binomial by taking tan² x as a common factor

∴ tan² x (tan² x + 2) = 0

∴ tan² x = 0

<em>OR</em>

∴ tan² x + 2 = 0

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∵ tan² x = 0 ⇒ take √ for both sides

∴ tan x = 0

∵ tan 0 = 0 , tan π = 0

∴ x = 0

∴ x = π

<em>OR</em>

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∴ tan² x = -2 ⇒ no square root for negative value

∴ tan² x = -2 is refused

∴ The solutions of the equation are 0 , π

4 0
3 years ago
Read 2 more answers
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