Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer: 6
Explanation: calculator
ANWSER
food, other, utilities, car, rent
EXPLANATION
u=13%
r=43%
f =1%
c=27%
o=7%
1%, 7%, 13%, 27%, 43%
We must find the common denominator.
The list of multiples of 4: 0, 4, 8, 12, 16, 20, ...
The list of multiples of 3: 0, 3, 6, 9, 12, 15, 18, ...
The common denominator is 12.

Therefore:

<h3>Answer: 17/12 = 1 5/12</h3>