Question

If u get this right u get branist

Answer 1

5(2)^2-2(7) = 6

6(7+2)/2 = 27

Therefor the correct answer is the < symbol.

I hope this helps! :)

Answer 2

Answer:

When e= 7 and f = 2, then $5f^2-2e$ is than $\frac{6(e+f)}{f}$.

Step-by-step explanation:

We are given that:

• e= 7
• f= 2

Using this, we can plug into the values into the following equation in order to figure out how the two equation relate.

1.  $5f^2-2e$
2. $5(2)^2-2(7)$
3. $5(4)-14$
4. $20 - 14$
5. $6$  

Now that the first equation is solved, lets solve the second equation.

1. $\frac{6(e+f)}{f}$
2. $\frac{6(7+2)}{2}$
3. $\frac{6* 7 + 6 *2}{2}$
4. $\frac{42 + 12}{2}$
5. $\frac{54}{2}$  
6. $27$

Therefore, when e= 7 and f = 2, then $5f^2-2e$ is than $\frac{6(e+f)}{f}$.