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2 years ago

If u get this right u get branist

Mathematics

2 answers:

Vladimir [108]2 years ago

7 0

5(2)^2-2(7) = 6

6(7+2)/2 = 27

Therefor the correct answer is the < symbol.

I hope this helps! :)

zzz [600]2 years ago

6 0

Answer:

When e= 7 and f = 2, then $5f^2-2e$ is than $\frac{6(e+f)}{f}$ .

Step-by-step explanation:

We are given that:

e= 7
f= 2

Using this, we can plug into the values into the following equation in order to figure out how the two equation relate.

$5f^2-2e$
$5(2)^2-2(7)$
$5(4)-14$
$20 - 14$
$6\\$

Now that the first equation is solved, lets solve the second equation.

$\frac{6(e+f)}{f}$
$\frac{6(7+2)}{2}$
$\frac{6* 7 + 6 *2}{2}$
$\frac{42 + 12}{2}$
$\frac{54}{2}$
$27$

Therefore, when e= 7 and f = 2, then $5f^2-2e$ is than $\frac{6(e+f)}{f}$ .

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Step-by-step explanation:

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3 years ago

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Answer:

The answer is B.

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Create a system of equations that can be used to determine the rental cost of each truck for the 1-day move. Be sure to specify

bogdanovich [222]

The equation are y = 0.59x + 29.95 for company A and y = 0.79x + 19.95 for company B.

<h3>Linear equation</h3>

Linear equation is in the form:

y = mx + b

where y,x are variables, m is the rate of change and b is the initial value of y.

Let y represent the total cost of rental for each truck in x hours.

From the table, for company A:

y = 0.59x + 29.95

For company B:

y = 0.79x + 19.95

The equation are y = 0.59x + 29.95 for company A and y = 0.79x + 19.95 for company B.

Find out more on linear equation at: brainly.com/question/14323743

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2 years ago

Which one is the right answer

Jobisdone [24]

Answer: A. f(g(x)) =x and g(f(x))=x and f and g are inverses.

Step-by-step explanation:

A function <em>g</em> is the inverse of function <em>f</em> if

Given: f(x)= x+4 , g(x) = x-4

f(g(x)) = f(x+4) = (x-4)+4

= x-4+4 = x

i.e. f(g(x)) =x

g(f(x))= g(x-4) = (x-4)+4 =x

i.e. g(f(x))=x

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2 years ago

Use the surface integral in Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus

Alinara [238K]

Answer:

The circulation of the field f(x) over curve C is Zero

Step-by-step explanation:

The function $f(x)=(x^{2},4x,z^{2})$ and curve C is ellipse of equation

$16x^{2} + 4y^{2} = 3$

Theory: Stokes Theorem is given by:

$I= \int \int\limits {{Curl f\cdot \hat{N }} \, dx$

Where, Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

Also, f(x) = (F1,F2,F3)

$\hat{N} = grad(g(x))$

Using Stokes Theorem,

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$\hat{N} = grad(16x^{2} + 4y^{2} - 3)$

$\hat{N} = (32x,8y,0)$

Now, $f(x)=(x^{2},4x,z^{2})$

Curl f(x) = $\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\\frac{∂}{∂x} &\frac{∂}{∂y} &\frac{∂}{∂z} \\F1&F2&F3\end{array}\right]$

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$I= \int \int\limits {Curl f\cdot \hat{N} } \, dx$

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I=0

Thus, The circulation of the field f(x) over curve C is Zero

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3 years ago