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2 years ago

One of the five quadratics below has a repeated root. (The other four have distinct roots.) What is the repeated root?

Mathematics

1 answer:

pychu [463]2 years ago

6 0

Answer:

Step-by-step explanation:

A quadratic with repeated roots will be a multiple of a perfect square trinomial. The form of it will be ...

a(x -b)² = ax² -2abx +ab² = a(x² -2bx +b²)

Dividing by the leading coefficient will leave a monic quadratic whose constant is a (positive) perfect square, and whose linear term has a coefficient that is double the root of the constant.

Dividing by the leading coefficient gives ...

x^2 -18x -81 . . . . . a negative constant

Dividing by the leading coefficient gives ...

x^2 -2x +3 . . . . . . constant is not a perfect square

Dividing by the leading coefficient gives ...

x^2 -4x +4 = (x -2)^2 . . . . . has a repeated root of x=2

Dividing by the leading coefficient gives ...

x^2 -1.2x -0.36 . . . . . . a negative constant

The x-coefficient is not 2 times the root of the constant.

14 = √196 ≠ 2√196

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The interior ages of a triangle have measure

Nina [5.8K]

Answer:

See below in bold.

Step-by-step explanation:

1. The 3 angles in a triangle add up to 180 degrees.

So x = 180 - (55 + 25)

= 180 - 80

= 100 degrees.

2. The 4 angles in a quadrilateral add up to 360 degrees,, so

3x + 127 + 54 + 119 = 360

3x + 300 = 360

3x = 360 - 300

3x = 60

x = 20 degrees.

3. Exterior angle

= 94 + 42

= 136 degrees.

3 0

4 years ago

Read 2 more answers

Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame

lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678$

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{207.9 - 208}{0.1678}$