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nasty-shy [4]
3 years ago
5

To which subset(s) does the negative square root of 25 belong? choose all that apply

Mathematics
2 answers:
melomori [17]3 years ago
8 0

Answer:

-5 is an integer and also a rational number.

Step-by-step explanation:

Given is a value which is the negative square root of 25 belong.

First find out square root of 25 as

\sqrt{25} =5\\-\sqrt{25}=-5

We know that -5 is not a natural number or whole number since negative

But -5 is a rational number and also an integer

lozanna [386]3 years ago
5 0
-\sqrt{25} which can be written as -sqrt(25) on a keyboard, can be simplified to -5 since the square root of 25 is 5.

Put another way, 5^2 = 25 so we're simply going in reverse.

So the question is: where does -5 belong? Which number set?

The answer is: the set of integers and rational numbers
So that's the two answers

----------------------------------------------------------------------------------

Extra Info:

The value -5 is not a natural number as the set of natural numbers is {1, 2, 3, 4, 5, ...} basically the set of counting numbers
The same story applies to the set of whole numbers which is {0, 1, 2, 3, ...} 
So -5 is not in the set of whole numbers

The value -5 is also not irrational because it is rational. We can write it as a ratio of two integers: -5 = -5/1
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Answer:

a)

x  |  y

==========

16  |  3

12  |  6

8   |  9

4   |  12

b) A large basket contains 23 eggs

Step-by-step explanation:

a) Isolating 3x, we get

3x = 60-4y

This means that 60-4y is a multiple of 3.

Besides, as x is a positive integer, then x = 60-4y has to be greater than zero

60-4y>0

Solving the inequality for y

60>4y

60/4 > y

15>y (or y<15, which is the same)

The multiples of 3 which are smaller than 15 are 3,6,9 and 12

Now we draw a table for these values of y and found the value of x by replacing in the equation 3x = 60-4y---> x = (60-4y)/3

x  |  y

=======

16  |  3

12  |  6

8   |  9

4   |  12

And these are all the solutions in positive integers.

b) This problem is pretty much like problem a)

Let's call x the number of eggs contained in the large baskets and y the number of eggs contained in the small baskets.

Then

Number of eggs bought - number of eggs sold = number of eggs left over.

In this case

11x-39y = 19

But we also know that 0<y<12 because the small baskets hols fewer than a dozen.

Isolating x in the equation 11x-39y + 19, we get

x=(19+39y)/11

Now we make a table with these values of x and y remembering that y is a positive integer smaller than 12

x   | y

=======

5.2  | 1

8.8  | 2

12.4 | 3

15.9 | 4

19.5 | 5

23   | 6

26.6 | 7

30.1 | 8

33.6 | 9

37.2 |10

40.7 |11

From this table we see that the only integer solution for x is 23, so a large basket contains 23 eggs.

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3 years ago
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