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IrinaVladis [17]
3 years ago
9

MiGuel ate 1/4 of a pizza in 1/2 of an hour. How long will it take Miguel to eat one pizza?

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

It will take  him 2 hours to eat a whole pizza

Step-by-step explanation:

There are 2 halves in an hour, and if he eats 1/4 of a pizza in half an hour, he will take 2 hours to eat a whole pizza.

Neko [114]3 years ago
3 0
2 hours to eat the whole pizza
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Simon can see two lights, light A and light B.
xz_007 [3.2K]

Answer:

2 Times

Step-by-step explanation:

Simon can see two lights A and B

  • Light A flashes every 15 seconds.
  • Light B flashes every 18 seconds.

First, we determine the next time both lights will flash together.

This is done by finding the Least Common Multiple of 15 and 18.

15=3X5

18=2X3^2

LCM of 15 and 18=2X3^2X5=90

This means that lights A and B will first flash together after 90 seconds.

Now, 240/90=2.\overline{6} seconds

Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times

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3 years ago
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notka56 [123]

Answer:

yes razi is correct pateran 3

Step-by-step explanation:

8 0
3 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
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LiRa [457]

Answer:

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3 years ago
How do you factor 45x^2+295x-140
Vaselesa [24]
I could explain it, but you have to ask me, other than that the answer is 5(x+7)(9x-4).
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3 years ago
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