Answer:
2 Times
Step-by-step explanation:
Simon can see two lights A and B
First, we determine the next time both lights will flash together.
This is done by finding the Least Common Multiple of 15 and 18.
15=3X5
18=
LCM of 15 and 18=
This means that lights A and B will first flash together after 90 seconds.
Now, 240/90= seconds
Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times
Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:
Compute the probability that none of the LED light bulbs are defective as follows:
Thus, the probability that none of the LED light bulbs are defective is 0.7374.