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3 years ago

Wat is the answer for 91²×14=

Mathematics

2 answers:

svet-max [94.6K]3 years ago

8 0

Answer:

115934

Step-by-step explanation:

calculator

Xelga [282]3 years ago

8 0

Step-by-step explanation:

91+91=182 ×14=2,548 I think this is the answer

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

I will try to give as many details as possible.

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

2 years ago

Help please! I just need to know how to do this step by step...

Alex787 [66]

-8 - 5n = 64 + 3n

+5n +5n add 5n to both sides, 5n's cancel out on the left.

______________

-8 = 64 + 8n

-64 -64 subtract 64 on both sides, 64's cancel out on the right.

______________

-72 = 8n

___ ___ divide 8 on both sides, 8's cancel out from the right.

8 8

n= -9, final answer

7 0

2 years ago

Read 2 more answers

8-4x=4-3(2x+6) ??? Someone help

Maurinko [17]

8 - 4x=4 - 3(2x+6)
<=> 8 - 4x = 4 - 6x - 18
<=> 8 - 4 + 18 = 4x - 6x
<=> 22 = -2x
x = -11

7 0

3 years ago

Read 2 more answers

In preparation for the Senior Prom, 8 seniors got together and decided to travel in style and rent a limousine. They investigate

Snowcat [4.5K]

The limousine will cost $240.
$180 for the first three hours, plus 30 for each hour after. They need two extra hours.
So, 180+30(2)=240.
They also want to leave a $20 dollar tip.
So, 240+20=260
That is $260 dollars they need to pay altogether.
Divide that number by the number of students and you'll get how much they each must pay.
260/8=32.50

$32.50 each.

♦Brainliest please♦

4 0

3 years ago

A boy walks 58 feet up a ramp having a 22.5 degree inclination. how high is he standing from the ground?

yKpoI14uk [10]

Boy is 22.5 feet high from the ground

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec). In geometry, trigonometry is a branch of mathematics that deals with the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with respect to sides and angles.

The given question can be solved by sin, as value of perpendicular is to be evaluated and height and angle is provided. Let height from the ground be x

sin(22.5°) = x / 58

x = 58sin22.5 = 58(.38258) = 22.5 feet high.

Thus the Boy is 22.5 feet high from the ground.

Learn more about trigonometry here :

brainly.com/question/26719838

#SPJ4

6 0

1 year ago