No, because one x-value corresponds to two different y-values
First we'll substitute
with 

Then we can separate this.

Then we'll solve this.



Then we'll plug in to find the extraneous solutions (if any)

Its the same thing because your just switching the order which doesn't matter when your adding or multiplying
The answer to this question will be A
<h3>
Answer:</h3>
C. x^5 + 5x^4y + 10x^3y^2 + 10x^2y^3 + 5xy^4 + y^5
<h3>
Step-by-step explanation:</h3>
Wrong terms are bolded:
A. x5 + 5x4y + 10x3y2 + 10x3y3 + 5xy4 + y5
B. x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + y4
C. x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + y5
D. x5 + 5x4y4 + 10x3y3 + 10x2y2 + 5xy + y5
The sum of exponents should always be 5.