Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
Answer:
x=2+
or x= 2-![\sqrt[]{2}\\](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B2%7D%5C%5C)
Step-by-step explanation:
Answer:
Send what?
Step-by-step explanation:
I need a better question
6.66, with a bar on top of the last two sixes