The mass that must be added is 0.628 kg
Explanation:
The period of a mass-spring system is given by
where
m is the mass
k is the spring constant
For the initial mass-spring system in the problem, we have
m = 0.500 kg
T = 1.36 s
Solving for k, we find the spring constant:
In the second part, we want the period of the same system to be
T = 2.04 s
Therefore, the mass on the spring in this case must be
Therefore, the mass that must be added is
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Answer:
I would believe that it would be the last option
Explanation:
Physical science is a type of science that mainly focuses on natural objects that are not alive, such as minerals and rocks.
True
I hope this helps and have a wonderful day filled with joy!!
Answer: Its the last one: The position of the block will change
Explanation: Since the forces are unbalanced, one side of the block will be stronger, therefore making the block move.
<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
