Question

PLEASE HELP I HAVE FINALSSS​

Answer 1

Answer: 26.67 m/s

Explanation:

Given

Length traveled by the ball $s=40\ m$

Time taken to reach the goal post is $t=3\ s$

Initial velocity $u=0\ m/s$

Using the second equation of motion

$\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2$

Now using

$\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s$

The velocity of ball will be 26.67 m/s