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Soloha48 [4]
2 years ago
6

PLEASE HELP I HAVE FINALSSS​

Physics
1 answer:
vitfil [10]2 years ago
8 0

Answer: 26.67 m/s

Explanation:

Given

Length traveled by the ball s=40\ m

Time taken to reach the goal post is t=3\ s

Initial velocity u=0\ m/s

Using the second equation of motion

\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\

Now using

\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s

The velocity of ball will be 26.67 m/s

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