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serg [7]
3 years ago
11

How is an object’s position in the solar system affect its motion and temperature?

Physics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

it will be base on the climate change.

Explanation: so let just say tomorrow it will be cold so the atmosphere will circle on the coolest atmosphere away from the sun.

You might be interested in
Radioactive isotopes are used in medicine to create images of internal
VMariaS [17]

Answer:

The correct option is D) Fission

Explanation:

There are several methods through which Radioactive isotopes are created.

  1. Using a nuclear reactor that has a field of neutrons, insert a stable sample such as Lutetium-176. When it gets bombarded with neutrons, it acquires some, and fission is said to have occurred. Note that when Lutetium-176 acquires a neutron, it becomes radioactive Lu-177.
  2. Fission is also used to create Fluorine-18. To obtain the same, you need to bombard pure or enriched [^{18} O] water with ~18 MeV protons which are high energy in nature. The bombarding is achieved using a cyclotron or an accelerator.

Cheers

3 0
3 years ago
If a 50 KG object is at a location 25,600 km from Earth's Center, what is the gravitational force exerted by the objects on Eart
masya89 [10]

Answer: The force exerted by the object on Earth is 30.4 N, and the direction is towards the object.

Explanation:

The gravitational force between two objects of mass M1 and M2, that are at a distance R between them is written as:

F = G*(M1*M2)/R^2

Where G is the gravitational constant, such that:

G = 6.674*1^(-11) m^3/(kg*s^2)

We know that M1, the mass of the object, is 50kg

R is the distance, in this case, is 25,600km

But this needs to be written in meters, remembering that:

1km = 1000m

Then:

25,600km = (25,600*1000)m = 25,600,000 m

And M2 is the mass of Earth, which is:

M2 = 5.972*10^(24) kg

Replacing all of those in the force equation we get

F = (6.674*1^(-11) m^3/(kg*s^2))*(50kg*5.972*10^(24) kg)/( 25,600,000 m)^2

F = 30.4 N

We know that the gravitational force is attractive, then the direction in which this force acts is towards the 50kg object.

Now, remember the second Newton's law is:

F = M*a

Then the acceleration that the object causes on Earth is:

30.4N = ( 5.972*10^(24) kg)*a

a = 30.4N/( ( 5.972*10^(24) kg)) = 5.09*10^(-24) m/s

This acceleration is almost despreciable.

5 0
3 years ago
How does density help scientists?
zimovet [89]
This quantity ρ is known as the density<span> , which is usually defined as the mass per unit volume: ρ = m/V. The volume units milliliter (mL) and cubic centimeter (cm</span>3<span>) are almost identical and are commonly used interchangeably. The general meaning of </span>density<span> is the amount of anything per unit volume.</span>
8 0
3 years ago
Read 2 more answers
An 88 kg person steps into a car of mass 2002 kg, causing it to sink 5.36 cm on itssprings. Assuming no damping, with what fre-q
Marina CMI [18]

Answer:

The required frequency = 0.442 Hz

Explanation:

Frequency f  = ( \dfrac{1}{2 \pi}) \omega

where;

\omega = \sqrt{\dfrac{k}{m} }

Then;

f = \Bigg ( \dfrac{1}{2 \pi}  \Bigg )   \Bigg( \sqrt{\dfrac{k}{m} }  \Bigg )

However;

k  = \dfrac{F}{x} and;

mass m = m_{car } + m_{person}

f = \Bigg ( \dfrac{1}{2 \pi}  \Bigg )   \Bigg( \sqrt{\dfrac{\dfrac{F}{x}}{m_{car}+m_{person}} }  \Bigg )

f = \Bigg ( \dfrac{1}{2 \pi}  \Bigg )   \Bigg( \sqrt{\dfrac{{F}}{x(m_{car}+m_{person})} }  \Bigg )

where;

F = m_{person}g

Then;

f = \Bigg ( \dfrac{1}{2 \pi}  \Bigg )   \Bigg( \sqrt{\dfrac{ {m_{person}g }}{x(m_{car}+m_{person})} }  \Bigg )

replacing the values;

f = \Bigg ( \dfrac{1}{2 \pi}  \Bigg )   \Bigg( \sqrt{\dfrac{ {(88 \ kg)* (9.81 \ m/s^2) }}{(5.36 \times 10^{-2} \ m) (2002 \ kg +88 \ kg)} }  \Bigg )

\mathbf{f = 0.442 \ Hz}

8 0
3 years ago
Which of the circuit offers greater resistance to the flow of current 1A or 2A ?
Dafna1 [17]
1 A offers greater resistance
7 0
3 years ago
Read 2 more answers
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