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3 years ago

13

Un movil que se desplaza a 20m/s aplica los frenos durante 5 segundos si al final de la frenada tiene una rapidez de 10m/s,calcu

lar la aceleracion

1 answer:

kaheart [24]3 years ago

5 0

aceleración= velocidad final - velocidad inicial ÷ el tiempo

a= 10-20÷5= -2 m/s

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Given s=1/2(v+u)t find t

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Explanation:

s=(v+u)t/2

2s/(v+u)=t

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3 years ago

A node is a point on a standing wave that has no displacement from the rest position. at the nodes, _____.

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3 years ago

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1.Particles are spaced the farthest apart in _____ and are the closest in ______. Select the answer that best completes the sent

Hunter-Best [27]

Answer:

gases; solids.

Explanation:

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3 years ago

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A coin placed on the cover of a book just begins to move when the cover makes an angle of 38 degrees with the horizontal. What i

RSB [31]

Answer:

m g sin theta = force of object along incline due to gravity

N μ = frictional of incline on object where N is the normal force

N = m g cos theta force perpendicular to incline

m g sin theta = N μ = μ m g cos theta

μ = tan theta = tan 38 = .78

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2 years ago

A 1000-kg car is moving at 40.0 km/hr when the driver slams on the brakes and skids to a stop (with locked brakes) over a distan

liq [111]

Answer:

skid distance = 180 m

Explanation:

given,

mass of the car = 1000 Kg

speed of the car = 40 Km/hr

distance to stop = 20 m

if speed is now = 120 Km/he

distance to stop = ?

from given question we can state that,

Work done by the friction is equal to the change in kinetic energy of the car.

$W= \dfrac{1}{2}mv^2$ ............(1)

And we also know that work is directly proportional to displacement

W = F × x...........................(2)

from the equation (1) and (2)

x ∝ v²

now,

here velocity is increased from 40 km/h to 120 km/h means velocity is increase 3 times

so displacement will be equal to 3² or 9 times

hence, skid distance will be equal to 9 x 20 = 180 m

skid distance = 180 m

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3 years ago