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4 years ago

9

20 POINTS!!!!!!!

2 answers:

exis [7]4 years ago

6 0

Hello,

y=a(x-h)^2+kvertex is (h,k)and when a is positive it opts up
svertex at -2,5
y=a(x+2)^2+5if we expand and set to zero0=ax²+4ax+4a+5dunnow how to solveI do know that A is positivealso since we gotvertex is (-2,5)it opens upthe vertex is the lowest point
the zeros are where y=0notice lowest point is (-2,5)5 is the lowest point5>0, so there are no zeroes
no solutions for that 2nd equation

madreJ [45]4 years ago

6 0

Answer: your correct answer would be no solution

Step-by-step explanation:

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