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3 years ago

How are patterns used to solve a problem?

1 answer:

7 0

It can be variety of problems but a x and y plot would be ideal demonstration as you need to make a hypothesis of what you think the pattern for it is then use it for each x and y problem through put the plot

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0.13x0.11=????????????????

andre [41]

Answer:

0.0143 in decimal form

Step-by-step explanation:

3 0

3 years ago

Marcy is drawing a stop sign to scale using letters that are 5 centimeters (cm) tall. What should be the width of her drawing of

sergejj [24]

Answer:20cm

Step-by-step explanation:

5 0

3 years ago

The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste and 2460 dollars for 135 kg of waste. (a)

Ulleksa [173]

Answer:

$C=18w+30$

Step-by-step explanation:

We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste

So, $(x_1,y_1)=(100,1830)$

We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.

So, $(x_2,y_2)=(135,2460)$

We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.

So, we will use two point slope form :

Formula : $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Substitute the values

$y-1830=\frac{2460-1830}{135-100}(x-100)$

$y-1830=18(x-100)$

$y-1830=18x-1800$

$y=18x-1800+1830$

$y=18x+30$

y denotes the cost

x denotes the weight

So, Replace y with C and x with w

$C=18w+30$

So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is $C=18w+30$

7 0

3 years ago

Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A samp

shutvik [7]

Answer:

0.9910 = 99.10% probability that a sample of 170 steady smokers spend between $19 and $21

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .