Answer:
10x^2 + 11x-6=0
Step-by-step explanation:
Answer:
The work done to pump all of the kerosene from the tank to an outlet is
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :
![dF=\pi R^{2}dy*50](https://tex.z-dn.net/?f=dF%3D%5Cpi%20R%5E%7B2%7Ddy%2A50)
This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.
![W=450\pi \int_{0}^{8}dy(8-y)](https://tex.z-dn.net/?f=W%3D450%5Cpi%20%5Cint_%7B0%7D%5E%7B8%7Ddy%288-y%29)
![W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)](https://tex.z-dn.net/?f=W%3D450%5Cpi%28%5Cint_%7B0%7D%5E%7B8%7D%208dy-%5Cint_%7B0%7D%5E%7B8%7D%20ydy%29)
![W=450\pi(8*8 -\frac{8^{2}}{2})](https://tex.z-dn.net/?f=W%3D450%5Cpi%288%2A8%20-%5Cfrac%7B8%5E%7B2%7D%7D%7B2%7D%29)
![W=450\pi(64 -\frac{64}{2})](https://tex.z-dn.net/?f=W%3D450%5Cpi%2864%20-%5Cfrac%7B64%7D%7B2%7D%29)
Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
Answer:
35
Step-by-step explanation: I used a protractor
Let price of one scarf be $x
Price of the other is 3 more than $x
Therefore price of the other scarf =$x +3
The total price she paid = $25.00
That is, x+x+3=25
2x+3=25
2x=25-3
2x=22
x=22/2
x=11
The price of one scarf is $11 and the price of the other is 11+3=$14
The price of the expensive scarf =$14.
At x=2, y=4
At x=4, y=16
So the total change in y from x=2 to x=4 is 16-4=12
And since average rate of change = total change in y divided by total change in x within the same period, therefore the answer is 12/2 = 6
Hope that helps. Let me know if you have any questions.