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Inessa [10]
4 years ago
11

Factor the quadratic expression Completely; -8x^2-15x+2

Mathematics
1 answer:
SSSSS [86.1K]4 years ago
4 0
(x + 2)(- 8x + 1) are your factors. 
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If three points are coplanar, they are also collinear true or false​
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no

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three points can exist on three different lines and still reside in the same plane

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Using the factorised trinomial <img src="https://tex.z-dn.net/?f=%28n-2%29%284n-7%29" id="TexFormula1" title="(n-2)(4n-7)" alt="
andrew-mc [135]
4n² - 15n + 14<span> is always the product of two numbers, for it to be prime number, one of these factors must be either 1 or -1.

Case n - 2 = 1
That would be n = 3
Then </span>4n² - 15n + 14<span> = 5 , which is prime.

Case n - 2 = -1
That would be n = 1
Then </span>4n<span>² - 15n + 14 = 3, which is also prime.

Case 4n - 7 = 1
That would be n = 2 and that makes other factor (n-2) zero so it's not prime

Case 4n-7 = -1
That would be n = 3/2 which is not integer, so </span>4n<span>² - 15n + 14 will not be interger.

For any other n values, </span>4n<span>² - 15n + 14 will be composite number since it is product of two factors.

Therefore we are left with n = 1 and n = 3; only two values of n.</span>
5 0
3 years ago
How much money would you need to deposit today at 7% annual interest
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$33,090.

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The formula is A = P( 1 + r/2)^2n so we have:

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P = 50000/ 1.035^12

= $33,090 to the nearest dollar.

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Expand (4x-2y)^3 for math final
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In general: <span>(a - b)^3 = a^3 - 3 a^2b + 3 a b^2 - b<span>^3
(4x-2y)^3 = </span></span>(4x)^3 - 3 (4x)^2(2y) + 3 (4x) (2y)^2 - (2y)^3
5 0
3 years ago
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