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Amiraneli [1.4K]
3 years ago
6

Marta runs a mandarin-orange fruit stand. She is talking to an employee, Maribel, on the phone and trying to tell her the equati

on needed to figure out how many oranges to send to a certain customer. The equation is 50 + one-half m = 120. Which statement should Marta say that will communicate the correct equation? Select all that apply. Fifty times the number of oranges is half of one-hundred-and-twenty. Fifty more than half the number of the oranges is one-hundred-and-twenty. The difference of fifty and half of the number of oranges is one-hundred-and-twenty. The sum of fifty and half the number of oranges is the same as one-hundred-twenty. Fifty more than half of the number of oranges.
Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

Fifty more than half the number of the oranges is one-hundred-and-twenty.

The sum of fifty and half the number of oranges is the same as one-hundred-twenty.

Step-by-step explanation:

The equation is 50 + one-half m = 120.

Assume the number of oranges=m

50+1/2m=120

1/2m=120-50

1/2m=70

m=70÷1/2

=140

All statement that applies includes:

1. Fifty more than half the number of the oranges is one-hundred-and-twenty.

50+1/2m=120

2. The sum of fifty and half the number of oranges is the same as one-hundred-twenty.

50+1/2m=120

Martha can use the two statements above to communicate the correct equation

Paul [167]3 years ago
3 0

Answer:

B-Fifty more then half the number of the oranges is one-hundred-and-twenty

D-The sum of fifty and half the number of oranges is the same as one-hundred-twenty

Step-by-step explanation:

B and D are the answers i took the test before answering so your good with me please leave a thanks  

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Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

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Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

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The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
4 years ago
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igor_vitrenko [27]
8.2/2.87 
=2.857143

:)

Hope this helps!
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