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Olin [163]
4 years ago
13

Solve for x in the equation x^2-10x+25=35.

Mathematics
2 answers:
lesya692 [45]4 years ago
5 0

Answer:

x_{1}=5+\sqrt{35}

x_{2}=5-\sqrt{35}

Step-by-step explanation:

the equation is

x^2-10x+25=35

to solve we need to make the equation equal to zero, for that we substract 35 on each side:

x^2-10x+25-35=0\\x^2-10x-10=0

we have now an equation in the general form: ax^2+bx+c=0

where

a=1

b=-10

c=-10

and we find the values for x with the general formula:

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}

substituting known values

x=\frac{-(-10)+-\sqrt{(-10)^2-4(1)(-10)} }{2(1)}\\x=\frac{10+-\sqrt{100+40} }{2}\\x=\frac{10+-\sqrt{140} }{2}\\x=\frac{10+-\sqrt{4*35} }{2}\\x=\frac{10+-2\sqrt{35} }{2}\\x=5+-\sqrt{35}

since we had a quadratic equation we will have 2 answers, one taking the positive sign and the other with the negative sign:

x_{1}=5+\sqrt{35} ≈ 10.916

x_{2}=5-\sqrt{35} ≈ -0.916

KatRina [158]4 years ago
3 0
So, this is too vague but I'll solve for both quadratic formula and find the discriminant.

Quadratic formula: <span>x=<span>5+<span><span><span>√35 OR</span><span> </span></span>x</span></span></span>=<span>5−<span>√<span>35
Finding the discriminant: 141</span></span></span>
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