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3 years ago

What is the degree when all sides of a triangle is added?

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

Answer:

180 degree

Step-by-step explanation:

When all sides of a triangle is added you will end up with 180 degree.

Hope this helps :D

jolli1 [7]3 years ago

5 0

The answer is 180 if each triangle is 60 degrees.

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3 years ago

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Karo-lina-s [1.5K]

Answer:

43 square cm

Step-by-step explanation:

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3 0

3 years ago

5, -10, 20, ...; 6th term<br> What is the 6th term?

aksik [14]

Answer:

Step-by-step explanation:

To get to -10 from 5 you have to subtract 15

to get to 20 from -10 you have to add 30

Repeat that process until you get to the 6th term.

5 (1st term)

5 - 15 = -10 (2nd term)

-10 + 30 = 20 (3rd term)

20 - 15 = 5 (4th term)

5 + 30 = 35 (5th term)

35 - 15 = 20 (6th term)

5 0

3 years ago

Verify tan(α+β) = [tan(α)+tan(β)] / [1 + tan(α)tan(β)]

mr Goodwill [35]

Answer:

Proved

Step-by-step explanation:

To Prove: $tan(\alpha+\beta) =\dfrac{tan(\alpha)+tan(\beta)}{1 + tan(\alpha)tan(\beta)}$

Proof:

Now: $tan \theta =\dfrac{sin\theta }{cos \theta}$

Therefore:

$tan (\alpha+\beta)=\dfrac{ sin (\alpha+\beta)}{cos (\alpha+\beta) }$

Applying these angle sum formula

$sin (\alpha+\beta)=sin \alpha cos \alpha + sin \beta cos \beta\\cos (\alpha+\beta)=cos \alpha cos \beta - sin \alpha sin \beta$

$tan (\alpha+\beta)=\dfrac{ sin \alpha cos \alpha + sin \beta cos \beta}{cos \alpha cos \beta - sin \alpha sin \beta }$

Divide all through by $cos \alpha cos \beta$

$tan (\alpha+\beta)=\dfrac{ (sin \alpha cos \alpha)/(cos \alpha cos \beta) + (sin \beta cos \beta)/(cos \alpha cos \beta)}{(cos \alpha cos \beta)/(cos \alpha cos \beta) - (sin \alpha sin \beta)/(cos \alpha cos \beta) }\\\\tan (\alpha+\beta)=\dfrac{\frac{sin \alpha}{cos \alpha}+\frac{sin \beta}{cos \beta} }{1-tan \alpha tan \beta} \\$Therefore:\\\\tan (\alpha+\beta)=\dfrac{tan \alpha+tan \beta}{1-tan \alpha tan \beta}$

=sin \alpha cos \beta + cos \alpha sin \beta/cos \alpha cos \beta/cos \alpha cos \beta- sin \alpha sin \beta/cos \alpha cos \beta

=sin \alpha/cos \alpha + sin \beta/cos \beta/1-tan \alpha tan \beta

=tan A + tan B/1-tan A tan B

5 0

3 years ago

What is the value of 9 in the number 49,258

pochemuha

9,000 is the answer.

7 0

3 years ago

Read 2 more answers