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djyliett [7]
3 years ago
8

Use the midpoint formula repeatedly to find the three points that divide the segment joining (x1, y1) and (x2, y2) into four equ

al parts
Mathematics
1 answer:
elixir [45]3 years ago
3 0
Midpoint is a point that divides a line segment into two parts that are equal or congruent. It is a point that is equidistant between the two endpoints. It would be the point that is found halfway the two endpoints. So, we obtain this point by locating the point that is in between the two endpoints. For the points (x1, y1) and (x2, y2), we determine the midpoint as follows:<span>

(x1+x2/2 , y1+y2/2) = (x3, y3)

So, we will have three points which are </span>(x1, y1), (x2, y2) and (x3, y3). Then, we need to use the formula again to determine the midpoint of the two line segment.
<span>

</span>(x1+x3/2 , y1+y3/2) = (x4, y4)
Substituting the value for x3 and y3,

(x1+((x1+x2)/2)/2 , y1+((y1+y2)/2)/2) = (x4, y4)
 (x4, y4) = (3x1 + x2 / 4 , 3y1 + y2 / 4)


(x3+x2/2 , y3+y2/2) = (x5, y5)
<span>We do the same as the procedure above,

</span>(x2+((x1+x2)/2)/2 , y2+((y1+y2)/2)/2) = (x4, y4)
 (x5, y5) = (3x2 + x1 / 4 , 3y2 + y1 / 4)<span>
</span><span>
</span>
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Which one would make me more money?
disa [49]

Answer:

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3 years ago
Sales Gi sells televisions. He earns a fixed amount for each television and an additional $15 if the buyer gets an extended warr
sveta [45]

Answer:

$65

Step-by-step explanation:

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Now divide 780/12 = $65

6 0
2 years ago
Bryan’s monthly electric bill is determined by adding a flat administration fee to the product of the number of kilowatt hours o
Sophie [7]
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
----------------------------
(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
-------------------------------------------------
(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 40
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 40/400
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 1/10
------------------------------------------------
if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
6 0
3 years ago
Read 2 more answers
How can you use properties to solve equations with variables on both sides
bija089 [108]
You can use properties to solve equations with variables on both side by simplifying get the variable on one side. solve using inverse operations then check to see if it fits in right .
5 0
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