A mis-hit golf ball flies straight up in the air. Exactly 4.0 seconds later it lands right next to the tee. How high up did the
1 answer:
Answer:
19.6 m
Explanation:
The total motion of the golf ball lasts 4.0 seconds: since the motion is symmetrical, it takes 2.0 s for the ball to reach the highest point and then another 2.0 s to land back on the tee.
Therefore, we can just analyze the second half of the motion that lasts
t = 2.0 s
During this time, the vertical distance covered by the ball is given by the equation:
where
u = 0 is the initial velocity (zero because the ball starts from its highest point, where the velocity is zero)
t = 2.0 s
g = 9.8 m/s^2 is the acceleration of gravity
Solving for d, we find:
So, the ball reaches a maximum height of 19.6 m.
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Explanation:
(a)
Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.
Using Snell's law as:
Where,
is the angle of incidence
is the angle of refraction = 90°
is the refractive index of the refraction medium
is the refractive index of the incidence medium
Thus,
The formula for the calculation of critical angle is:
Where,
is the critical angle
(b)
No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.
Answer:
(c) 16 m/s²
Explanation:
The position is .
The velocity is the first time-derivative of <em>r(t).</em>
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The acceleration is the first time-derivative of the velocity.
Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,
Its magnitude is 16 m/s².