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Alex787 [66]
3 years ago
8

You used 100 N of force to push a shopping cart 5m down the aisle in the grocery store. How much work did you do? *

Physics
2 answers:
ahrayia [7]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 500 \ Joules}}

Explanation:

Work can be found by multiplying the force by the distance.

W=F*d

The force is 100 Newtons and the distance is 5 meters. Therefore,

F= 100 \ N \\d=  5 \ m

We can substitute the values into the formula.

W= 100 \ N * 5 \ m

Multiply.

W= 500 \ N*m

  • 1 Newton meter is equal to 1 Joule.
  • Thus, our answer of 500 Newton meters is equal to 500 Joules.

W= 500 \ J

You did <u>500 Joules </u>of work to push a shopping cart 5 meters with a force of 100 Newtons.

Art [367]3 years ago
4 0

Answer:

<h2><u>Given</u><u> </u><u>:</u><u>-</u></h2>
  • Force (F) = 100 N
  • Displacement (D) = 5 m
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>

Work done

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

As we know that Work done is the product of Force and displacement

\tt \: w = force \:  \times displacement

\tt \: w = 100 \times 5

\tt \: w = 500 \: j

Therefore, Work done is 500 Joule

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C.c<span>onduction,  is the transfers of heat between substances that are in direct contact.</span>
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3 years ago
Using 15 percent as machine energy efficiency, what is the actual work output if the total work input is 7500 kilojoules​?
g100num [7]

Answer:

The actual work output is 1,125 kilojoules.

Explanation:

Energy efficiency is defined as the efficient use of energy. An appliance, process, or facility is energy efficient when it consumes less than the average amount of energy to perform an activity. Then, energy efficiency is the ratio between the amount of energy used in an activity and the amount expected to be carried out.

Efficiency is calculated as:

efficiency = output / input

Where output is the amount of mechanical work (in watts) or energy consumed by the process (in joules), and input (input) is the amount of work or energy that is used as input to carry out the process.

In this case:

  • Efficiency always has a value between 0 and 1. In this case, efficiency=0.15
  • output=?
  • input= 7500 kilojoules

Replacing:

0.15=output/7500 kilojoules

Solving:

Output=0.15* 7500 kilojoules

output=1,125 kilojoules

<u><em>The actual work output is 1,125 kilojoules.</em></u>

7 0
3 years ago
When a force is applied to an object, no work is being preformed on the object unless the object____.
Temka [501]
No work is being performed on the object unless the object is moving, as work done = force x distance
8 0
3 years ago
I’ll give points plz and brainliest I know the result I just need the process.
shusha [124]
Shiddd ion even know but can you like my comment?
7 0
3 years ago
Answer ?
morpeh [17]

Answer:

2.75 m/s^2

Explanation:

The airplane's acceleration on the runway was 2.75 m/s^2

We can find the acceleration by using the equation: a = (v-u)/t

where a is acceleration, v is final velocity, u is initial velocity, and t is time.

In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1

a = 2.75 m/s^2

5 0
2 years ago
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