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musickatia [10]
4 years ago
7

Why can we see the entire side of the moon during a full moon?

Physics
1 answer:
Rzqust [24]4 years ago
3 0

Answer: Its because instead of the sun being behind the earth therefor causing a shadow on the moon, it is away from the earth or behind the moon causing an eclipse.

Explanation: When the shadow of the earth is on the moon, it causes a shadow on the moon because the earth is a sphere. When the sun rotates away from the moon it prevents a shadow on the moon. Therefore causing a full moon and letting us see the entire side of the moon.

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The articles of confederation represented the Americans distrust of what form of government?
kondaur [170]

Answer: The Articles of Confederation were against having a strong central government.

Explanation:

7 0
3 years ago
The 0.41-kg cup of a James Bond anti-Martini-Maker is attached to a spring of spring constant 110 N/m. The cup is displaced hori
ehidna [41]

Answer:

Option B is the correct answer.

Explanation:

Period of a spring is given by the expression

            T=2\pi \sqrt{\frac{m}{k}}

Here, spring constant, k = 110 N/m

         Mass = 0.41 kg

Substituting,

        T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{0.41}{110}}=0.38s

Option B is the correct answer.

5 0
3 years ago
The unit of measurement of temperature is degree ______ Or degree __________​
ElenaW [278]

Answer:

none of above. The answer is celsius

5 0
3 years ago
Read 2 more answers
Consider a car driving around a circular track. Once started, the driver maintains a speed of 45 m/h. Compare the driver's veloc
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8 0
3 years ago
A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s.
Kruka [31]
It accelerates from rest at 1.1 m/s^2 for 20s. 

<span>s = at^2/2 </span>
<span>s = (.5)(1.1)(20)^2= 220m </span>

<span>then it travels 1100m </span>

<span>Then it slows down at 2.2m/s^2 until it stops at the station. </span>

<span>Calculate the train's speed: </span>
<span>v = at </span>
<span>v = (1.1)(20) = 22m/s 
</span>
<span>Now, calculate the time to stop: </span>
<span>v = at </span>
<span>t = 22/2.2 = 10s </span>
<span>s = t(u+v)/2 </span>
<span>s = 10(0+22)/2 = 110m </span>

<span>(A) Total distance = 220 +1100+110 = 1430m </span>

<span>(B) Time = 20 + 1100/22 + 10 = 80s</span>
6 0
4 years ago
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