Answer:
You would use the formula y=mx+b, where m is the slope and b is the y intercept.
Step-by-step explanation:
If the slope was 1/2 and the y intercept was 2, it would be y=1/2x+2
Answer:
the area of the triangle is 17.4cm^2
Step-by-step explanation:
Finding the area of a triangle
an isosceles triangle has two sides of equal length.
therefore to get the base of the triangle :
we need to subtract the lengths from he perimeter
30-12-12
= 6
<u>the base of the triangle is 6 cm</u>
<u></u>
<h3><u>area of a triangle</u></h3>
formula :
![\frac{1}{2} * base * height\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%20base%20%2A%20height%5C%5C)
<h3><u>getting the height of the triangle:</u></h3>
we make use of one side of the triangle , half the base. this creates a right angled triangle
we can make use of the formula
![c^{2} = a^{2} + b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%20%3D%20a%5E%7B2%7D%20%2B%20b%5E%7B2%7D)
were c is the hypotenuse of 12 cm
a is the adjacent of base (6/2) = 3 cm
and b is the height
![12^{2} = 3^{2} +b^{2}](https://tex.z-dn.net/?f=12%5E%7B2%7D%20%3D%203%5E%7B2%7D%20%2Bb%5E%7B2%7D)
![b^{2} = 12^{2} - 3^{2}](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%2012%5E%7B2%7D%20-%203%5E%7B2%7D)
![b^{2} = 135\\](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20135%5C%5C)
![b = \sqrt{135}](https://tex.z-dn.net/?f=b%20%3D%20%5Csqrt%7B135%7D)
b = 11.6 cm to 3sf
<u>the height is 11.6cm.</u>
<u></u>
<em>area of the triangle is :</em>
1/2 * 3 * 11.6
<u>= 17.4 cm^2</u>
<u />
<u>the area of the triangle is 17.4cm^2</u>
C) 54 is correct
Multiply all numbers! Mark with crown!
Answer:
11.25 // 11 ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
Step-by-step explanation:
15×0.75