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dlinn [17]
3 years ago
10

Worth all my points plus brainliest!!! Due in 4 hrs 1-11

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

1. 15

2. -8/9

3. 5

4. 7

5. a = 20

6. n = 100

7. 3.6 x 10^1

8. 3

9. 4

10. 8.37 x 10^5

11. 6.67 x 10^3

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The sum of 3 consecutive integral numbers is 117. Find the numbers.
timama [110]

Answer:

38, 39, and 40

Step-by-step explanation:

Let the three (3) consecutive integral numbers be:  

n  

n + 1  

n + 2  

Add the numbers together:  

n + n + 1 + n + 2  

Combine like terms:  

n + n + n = 3n  

1 + 2 = 3  

Therefore:  

3n + 3 = 117  

Subtract 3 from each side of the equation.  

3n + 3 - 3 = 117 - 3  

 

Combine like terms:  

3 - 3 = 0  

117 - 3 = 114  

3n = 114  

Divide each side by 3  

3n/3 = 114/3  

n = 38  

n + 1 = 38 + 1 = 39  

n + 2 = 38 + 2 = 40  

Check: 38 + 39 + 40 = 117  

The three (3) consecutive integral numbers are:  

38, 39, and 40.

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4 years ago
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3 years ago
Write a trinomial of degree 35
adoni [48]
We,know that
Trinomial of degree 35 means a polynomial that 
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