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saw5 [17]
3 years ago
5

Jericho is a botanist and is researching a particular species of plant. He found that the number of plants in his testing enviro

nment increases by 60% each year. The given function represents the number of plants in his testing environment after t years.
f(t)=30(1.60)^t

Which statement is true?

A.
The expression (1.38)6t reveals the approximate rate of increase in the number of plants when measured six times a year.
B.
The expression (1.48)2t reveals the approximate rate of increase in the number of plants when measured twice a year.
C.
The expression (1.01)6t reveals the approximate rate of increase in the number of plants when measured six times a year.
D.
The expression (1.26)2t reveals the approximate rate of increase in the number of plants when measured twice a year.
Mathematics
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

c is the answer ;) hope this helps

Naddika [18.5K]3 years ago
8 0
C Is The Answer It’s The Only One That Makes Sense
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3 to the 2 power plus (9-5)
QveST [7]

Answer:

{3}^{2}  + (9 - 5) \\  = 9 + 4 \\  = 13

3 0
2 years ago
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Find the difference quotient <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D" id="TexFor
AlladinOne [14]

Answer:

-2x - h - 3

Step-by-step explanation:

Step 1: Define

Difference Quotient: \frac{f(x+h)-f(x)}{h}

f(x) = -x² - 3x + 1

f(x + h) means that x = (x + h)

f(x) is just the normal function

Step 2: Find difference quotient

  1. <u>Substitute:</u> \frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}
  2. <u>Expand and Distribute:</u> \frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}
  3. <u>Distribute:</u> \frac{-x^2-2hx-h^2-3x-3h+1+x^2+3x-1}{h}
  4. <u>Combine like terms:</u> \frac{-2hx-h^2-3h}{h}
  5. <u>Factor out </u><em><u>h</u></em><u>:</u> \frac{h(-2x-h-3)}{h}
  6. <u>Simplify:</u> -2x - h - 3

8 0
3 years ago
Read 2 more answers
The function y = x 2 - 10x + 31 has a ____
katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

8 0
3 years ago
Race car driver Mario won 3 races and earn 75 points for each win. During the fourth race, he had dedications of 55 points, 104
svet-max [94.6K]

Answer:

he has 472 points now.

Step-by-step explanation:

5 0
4 years ago
Leftover Expression
Mumz [18]

The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.

Answer:

The equivalent expressions are;

8a + 2 and 6a + 6b

Step-by-step explanation:

The two leftover expressions are given as;

2(4x + 1) and 6(a + b)

In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.

Thus simply means expanding or collecting like times to make it clearer.

Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.

Thus;

2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;

8x + 2

Similarly,

6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;

6a + 6b

Thus;

The equivalent expressions are;

8a + 2 and 6a + 6b

4 0
3 years ago
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