Question

Write the equation of a line that is perpendicular to y =3x-2 and that passes through the point(-9,5)

Answer 1

Answer:

y = -1/3x + 8

Step-by-step explanation:

If two lines are perpendicular, the signs of the slope must be opposite and the slopes are reciprocals.

(basically if one is say -2/3, the other is 3/2. just flip it upside down)

So this slope is 3, so the new slope should be -1/3

The equation is now y = -1/3x + b

To find b, substitute (-9,5) in the equation

y = -1/3x + b

5 = -1/3(9) + b

5 = -3 + b

8 = b

So the equation is y = -1/3x + b

Answer 2

Answer:

y = -1/3x + 2

Step-by-step explanation:

I dont know who verified the other guy but he is wrong