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11Alexandr11 [23.1K]
3 years ago
6

Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (Assume that

n begins with 1.) −5, 10 3 , − 20 9 , 40 27 , − 80 81 , ...
Mathematics
1 answer:
mezya [45]3 years ago
8 0

Answer:

The formula to the sequence

-5, 10/3, -20/9, 40/27, -80/81, ...

is

(-1)^n. 5×2^(n-1). 3^(1-n)

For n = 1, 2, 3, ...

Step-by-step explanation:

The sequence is

-5, 10/3, -20/9, 40/27, -80/81, ...

By inspection, we see the following

- The numbers are alternating between - and +

- The numerator of a number is twice the numerator of the preceding number. The first number is 5.

- The denominator of a number is 3 raised to the power of (1 minus the position of the number)

Using these, we can write a formula for the sequence.

(-1)^n for n = 1, 2, 3, ... takes care of the alternation between + and -

5×2^(n-1) for n = 1, 2, 3, ... takes care of the numerators 5, 10, 20, 40, ...

3^(1-n) for n = 1, 2, 3, ... takes care of the denominators 1, 3, 9, 27, ...

Combining these, we have the formula to be

(-1)^n. 5×2^(n-1). 3^(1-n)

For n = 1, 2, 3, ...

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Part A: The Sun produces 3.9 ⋅ 1033 ergs of radiant energy per second. How many ergs of radiant energy does the Sun produce in 3
Nuetrik [128]

5914 1404 393

Answer:

  A) 1.3×10^37 ergs

  B) 1.435×10^3 mm

Step-by-step explanation:

A) The amount of energy will be the product of the energy rate and time:

  (3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs

  = 1.2675×10^(1+36) ergs

  = 1.2675×10^37 ergs ≈ 1.3×10^37 ergs

The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.

The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.

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B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.

On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.

  1.435×10^3 mm is more reasonable

8 0
3 years ago
Piper earned a grade of 57% on her multiple choice science final that had a total of 200 problems. How many problems on the fina
omeli [17]

Answer:

.57 x 200 = 114

Step-by-step explanation:

please mark brainliest

8 0
3 years ago
Read 2 more answers
Need help on 2,3,& 4 please help will give brainliest
muminat
Im not so sure about Q2 but 3 and 4 are correct for sure.

8 0
4 years ago
Convert -3(4+7) to word statements
Alex787 [66]

Answer:

-14

Step-by-step explanation:

4+7=11 so therefore -3-11=-14

3 0
3 years ago
Read 2 more answers
Plz help i will give 70 points
uysha [10]

SW= MP

RV=DL

LAst one is

AN= KG

this pointed in a differ direction fix it the the same direction as the top one.

like number 1: SW is similar MP because then are similar but just differ letters hope that helps.

5 0
3 years ago
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