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ValentinkaMS [17]
3 years ago
5

A contractor is considering a project that promises a profit of $46,000 with a probability of 0.7, or a loss (due to bad weather

, strikes, and such) of $12,000 with a probability of 0.3.
If many projects have these same probabilities and costs, how much should the contractor expect to earn on average per contract?
Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

$28,600

Step-by-step explanation:

Probably of 0.7 = 46000

Probability of 0.3 = 12000

The average profit = Sum of (x*Pr(x)

=0.7(46000) + 0.3(-12000)

= 32200 - 3600

= $28,600

The contractor should expect to earn $28,600 on the average

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Answer:

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Step-by-step explanation:

Note the side values of a 30-60-90 triangle. The answer is 1, √3 , 2, with 1 being the shortest side, and 2 being the hypotenuse.

For example:

10 , 10√3 , 20 can be the side measurements of a triangle.

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RoseWind [281]

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1) Is more representative

Step-by-step explanation:

The problem with his selection is that maybe there are few students participating in certain sport and those students maybe do quite more excercise than the rest (or quite less). This will modify the results because the sample he selected is biased. This problem wont be solved by method 3 or 4, because he is still selecting students that may modify heavily the results with a high probability

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If he has a list with all seventh grade students, each student is equallly likely to be selected and as a consequence, the the results wont be biased. Approach 1 is the best one.

5 0
3 years ago
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D

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Hope this helps,

Trey

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