Question

Find the square of rhe leg b of this right triangle a=2b, c=10

Answer 1

a^2+b^2=c^2

where c=25 m. and a=2b-10 m.

substitute

(2b-10)^2+b^2=25^2

4b^2-40b+100+b^2=625

5b^2-40b+100=625

divide both sides by 5

b^2-8b+20=125

subtract 20 from both sides

b^2-8b=105

complete the square

take half of 8 and square it=16

i hope this helps =3