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adelina 88 [10]
3 years ago
15

Find the missing side of a right triangle a b c

Mathematics
2 answers:
iren2701 [21]3 years ago
5 0

Answer:

Use Pythagorean Theorem.

Step-by-step explanation:

To find any side of a right angled triangle, we use Pythagorean Theorem. It states that the square of hypotenuse is equal to the sum of squares of it's sides.

Let hypotenuse is a

Perpendicular is b

and base is c

According to the theorem:

a²= b² + c²

Add values and solve for the unknown variable / side.

If you had added the problem, I would have elaborated more but still this will help you out.

barxatty [35]3 years ago
3 0
The person above is totally right, they provided all the right information but if you need help with a specific problem please provide a picture
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Please explain with working!!! Find the set of values of x that satisfy the inequality 9x^2-15x<6
Oksi-84 [34.3K]

Answer:

-1/3

Step-by-step explanation:

When solving a quadratic inequality, first solve it normally like you would for a normal quadratic equation. We have:

9x^2-15x

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9x^2-15x=6

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9x^2-15x-6=0

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-6 and 1 works. Thus:

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Now, we need to replace the equal signs with symbols again. To do so, we need to test which symbol to place. Let's do the first zero first.

So, the first zero is:

x=-1/3

Assume that the correct symbol is >. Thus,

x>-1/3

Now, pick any number that is greater than -1/3. I'll pick 0 since it's the easiest. Now, plug 0 back into the very original inequality. If it works, then the sign is correct, if it doesn't, then simply use the opposite one. Therefore:

9x^2-15x

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For the second one, do the same thing. We have:

x=2

Assume that the correct symbol is <. Thus:

x

Again, pick any number less than 2. I'm going to use 0. Plug 0 back into the original equation

9x^2-15x

Again, this is correct. Therefore, x<2 is also the correct inequality.

So together, we have:

x>-1/3 \text{ and } x

Together, we can write them as:

-1/3

(Note that we don't need to worry about the "or equal to" part since the original inequality didn't have it.)

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