place parentheses in the equation below so that you solve by finding the difference between 28 and 3 Write the answer 4×7-3=
1 answer:
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Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴
∵ DE : CD = 5 : 3
∴
∴ KD = 5/3 KC
∵ KE = KC + 8
∵
∴
∴
∴
∴
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
Answer:
(x - 6)² + (y - 2)² = 128
Step-by-step explanation:
Given as the circle has center ( 6 , 2)
and it passes through points (-2 , -6)
Now , standard equation of circle is (x -a)² + (y- b)² = r² , where (a , b) is center and r is the radius .
Again from given center the circle equation is
(x- 6)² + (y- 2)² = r²
Now this circle passes through points (-2 , -6)
so, (-2 -6)² + (-6 -2)² = r²
so, 8² + 8² = r²
Or, 128 = r²
i.e Radius pf this circle = 8
Hence the circle equation formed is
(x- 6)² +( y-2)² = 128 Answer