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7nadin3 [17]
3 years ago
13

The distance traveled by a certain vehicle varies directly to the amount of fuel the vehicle consumes. The vehicle traveled 90 m

ile on 5 gallons of fuel. At the same rate, how far would the vehicle travel on 7 gallons of fuel
Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

The vehicle covers 126 miles on 7 gallons of fuel.

Step-by-step explanation:

Given:

The distance traveled is directly proportional to the amount of fuel.

For F gallons of fuel distance traveled D miles can be given as:

D ∝ F

D=kF

where k is constant of proportionality.

The vehicle covers D=90 miles on F=5 gallons.

So

90=k(5)

Dividing both sides by 5.

\frac{90}{5}=\frac{k(5)}{5}

18=k

∴ k=18

When F=7 gallons

D=(18)(7)

D=126 miles

∴ The vehicle covers 126 miles on 7 gallons of fuel.

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Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

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We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

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\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

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System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

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The statistic for this case would be:

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And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

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