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3 years ago

A ranch has 3475 cattle. Between which two thousands is this number?

Mathematics

1 answer:

vekshin13 years ago

7 0

3,000 and 4,000 because that number is between these two thousands

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How to find the maximum height projectile motion?

ziro4ka [17]

Y=v(initial)*t+1/2at^2
since the velocity is zero at the maximum height then we get
y=1/2at^2
a is just acceleration due to gravity so a=g which is 9.8 m/s^2.
so y=1/2gt^2.

7 0

4 years ago

Two smoothies and an ice cream cone cost $7.50. Three smoothies and two ice cream cones cost $12. Calculate the cost of a smooth

anygoal [31]

Answer:

Smoothie = 3

Ice cream = 1.5

Step-by-step explanation:

2s + i = 7.5

3s + 2i = 12

subtract the equations

(3s + 2i) - (2s + i) = s + i

s + i = 4.5

2s + i = 7.5, so s must equal 3 (7.5 - 4.5)

If s = 3, then i is 1.5 (4.5 - 3.5)

To check, plug 3 and 1.5 into s and i.

2(3) + 1.5 = 7.5

6 + 1.5 = 7.5

7.5 = 7.5

3(3) + 2(1.5) = 12

9 + 3 = 12

12 = 12

5 0

3 years ago

The volume of a cone is 31.4 cm3 and the radius is 2 cm. What is the height of the cone? Use 3.14 for π. Round to the nearest te

kupik [55]

It's (B) 7.5 cm

h= (3V) / (πr^2)

8 0

3 years ago

Read 2 more answers

-2x-2y=4 solve this

Ierofanga [76]

Y=4-x that's the answer

6 0

4 years ago

Read 2 more answers

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago