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drek231 [11]
3 years ago
14

-6x - 2x = 40. Calculate and show work

Mathematics
2 answers:
Roman55 [17]3 years ago
8 0
Solve any algebraic expression by getting the x on one side (usually the left-hand side) and everything else and the opposite side (usually the right-hand side).

We do this by using the inverse operation of what is being done to the variable. If something is adding to the variable, say like an expression like x + 10, then we use subtraction to get rid of the addition and vice versa.

Similar to multiplication, we use division to cancel out the multiplication and vice versa.

If there are any like terms, we combine them. I will assume that you know how to combine like terms, but in short, to combine like terms, add the coefficients together and use the common variables and power. If there is no coefficient, then a 1 is implied. Similarly, if no explicit power is shown, then a 1 is implied.

-6x - 2x = 40
-8x        = 40

-6x and -2x are like terms because they have the same variable and are to the same power.

-6x + (-2)x
(-6 - 2)x
-8x

Now we have the expression -8x = 40. Now we can use division to get rid of the -8 juxtaposed to the variable x.

-8x = 40
-8x / 8 = 40 / -8
x = -5

xxMikexx [17]3 years ago
3 0
-6x-2x= 40
-8x=40
X= 40/-8
X= -5
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2 years ago
A local charity is selling seats to a baseball game. Seats cost $24 each, and snacks cost an additional $6
Crazy boy [7]

Answer:

To raise exactly $240, the charity needs to sell 20 snacks.

Step-by-step explanation:

Let

s = number of seats sold

y = number of snacks sold

Seats cost $24 each, then s seats cost $24s.

Snacks cost an additional $6 each, then y snacks cost $6y.

In total, s seats and y snacks cost $(24s+6y).

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If 5 seats are sold, then

24\cdot 5+6y=240\\ \\120+6y=240\\ \\6y=240-120\\ \\6y=120\\ \\y=20

To raise exactly $240, the charity needs to sell 20 snacks.

To solve this problem graphically, plot the graph of the line 24s+6y=240 and find on this line point with s-coordinate 5. This is exactly point (5,20), so the charity needs to sell 20 snacks.

5 0
3 years ago
Which of the following is the solution to | x -12 | < 15
KiRa [710]
Hello,
Answer D    -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12  U 12≤x<27 ⇔ -3<x<27

7 0
3 years ago
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patriot [66]
1) -12x

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3) false
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3 years ago
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