you need to get a common denominator and subtract 20/32 from 26/32
z would equal 6
Answer:
No you cannot.
Step-by-step explanation:
Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.
For Machine A, we have 4 cockpits; this would take 4c time. We also have 6 propulsion systems; this would take 6p time. Together it takes 26 hours; this would give us
4c+6p=26.
For Machine B, we have 8 cockpits; this would take 8c time. We also have 12 propulsion systems; this would take 12p time. Together it takes 56 hours; this would give us
8c+12p=56
This gives us the system
To solve this, we want the coefficients of one of the variables to be the same. To make the coefficients of c the same, we can multiply the top equation by 2:
To cancel c, we will subtract the second equation from the first one. However, this also cancels p:
We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.
Answer:
0.8508
Step-by-step explanation:
In this question, we are asked to estimate the probability of getting at least 12 correct answers.
X ~ Bin ( n , p)
Where n = 60 , p = 1/4 = 0.25
Mean = np = 60 * 0.25 = 15
Standard deviation = sqrt [ n p ( 1 - p) ] = Sqrt [ 60 * 0.25 ( 1 - 0.25) ] = 3.3541
Using normal approximation
P(X < x) = P(Z < ( x - mean) / SD )
P(X >= 12) = P(X > 11.5)
= P(Z > ( 11.5 - 15) / 3.3541 )
= P(Z > -1.04)
= P(Z < 1.04)
= 0.8508
Answer:
85x−12
Step-by-step explanation:
Yes, if the rule is
... output = input + 12
you add 12 to whatever input value you might have. For an input of 6, this is
... output = 6 + 12 = 18