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2 years ago

How does f(4) if f(x) = 2x work? how do i work this out?

Mathematics

1 answer:

sveta [45]2 years ago

6 0

So just plug in the 4 wherever you see an x. so it is f(4)=2(4)

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A set of data has a sample mean of 65.4 and a standard deviation of 1.2. If the sample size is 45. what is the 99% confidence in

bagirrra123 [75]

67.55 is the correct answe bec I add

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3 years ago

What is the number 0.00000482 written in scientific notation?

Elena L [17]

Move the decimal so that there is one whole number.

0.00000482 => 4.82

We moved 6 units to the left so:

4.82 * 10^-6

3 0

3 years ago

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If you shift the exponential parent function, f(x) = 2^x , right 2 units, what is the equation of the new function?

aev [14]

Answer:

$g(x)=2^{x-2}$

Step-by-step explanation:

<u>Translations</u>

For $a > 0$

$f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}$

$f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}$

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

Parent function: $f(x)=2^x$

Translated 2 units right: $g(x)=f(x-2)=2^{x-2}$

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1 year ago

Read 2 more answers

Compare and order from least to greatest 4/5, 3/12 and 5/6?

jonny [76]

The Answer: 3/12, 5/6, 4/5...

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3 years ago

PLEASE HELP the formula m=12,000+12,000rt/12t gives keri's monthly loan payment where t is the annual interest rate and t is the

tatiyna

Answer:

The answer is below

Step-by-step explanation:

The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.

Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

$m=\frac{12000+12000rt}{12t}\\ but\ m\leq275, \ and \ r=10\%=0.1\\275= \frac{12000+12000(0.1)t}{12t}\\275= \frac{12000}{12t} +\frac{12000(0.1)}{12t}\\275= \frac{1000}{t} + 100\\275-100= \frac{1000}{t} \\175= \frac{1000}{t} \\175t = 1000\\t= \frac{1000}{175}\\ t=5.72\ years$

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%

3 0

3 years ago