probability that it will have no errors in poisson distribution is 1/ 2 (e ^−3 + e ^−4.2 ).
Given the event Ti that the article is typed by the ith typist, the number of error follows a Poisson distribution with λi
where λ1 = 3 and λ2 = 4.2.
So P(no error) = P(no error| T1)P(T1) + P(no error| T2)P(T2)
= e^ −3 (3)0 / 0! × 1 /2 + e ^−4.2 (4.2)0 / 0! × 1 /2
= 1/ 2 (e ^−3 + e ^−4.2 ).
Learn more about the poisson distribution here:
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